How do you find the derivative of #y=tan(2x)# ?
1 Answer
Apr 7, 2018
Explanation:
#"differentiate using the "color(blue)"chain rule"#
#"Given "y=f(g(x))" then"#
#dy/dx=f'(g(x))xxg'(x)larrcolor(blue)"chain rule"#
#"here "y=tan2x#
#rArrdy/dx=sec^2 2x xxd/dx(2x)=2sec^2 2x#
