How do you find the derivative of $y= (x^2+3x+5)^(1/4)$ ?

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Answer 1 · 2014-09-19T14:16:06

By Chain Rule and Power Rule,

$y'=1/4(x^2+3x+5)^{1/4-1}cdot(x^2+3x+5)'$

$=1/4(x^2+3x+5)^{-3/4}(2x+3)$

How do you find the derivative of y= (x^2+3x+5)^(1/4)y= (x^2+3x+5)^(1/4) ?