Question

How do you find the derivative of `y= (x^2+3x+5)^(1/4)` ?

Answer 1

By Chain Rule and Power Rule,

`y'=1/4(x^2+3x+5)^{1/4-1}cdot(x^2+3x+5)'`

`=1/4(x^2+3x+5)^{-3/4}(2x+3)`