How do you find the derivative of #Y= ( x^3 + 5x^2 - 3 )( x^2 - 1 )^5#? Calculus Basic Differentiation Rules Product Rule 1 Answer Nallasivam V Aug 26, 2015 Refer explanation section Explanation: Y=#(x^3+5x^2−3)(x^2−1)^5# #dy/dx#= #(x^3+5x^2−3)(5)(x^2 - 1)^4(2x)+(x^2−1)^5(3x^2 + 10x)# #dy/dx#= #(x^3+5x^2−3)(10x)(x^2 - 1)^4+(x^2−1)^5(3x^2 + 10x)# #dy/dx#= #(10x^4+50x^3−30x)(x^2 - 1)^4+(x^2−1)^5(3x^2 + 10x)# Answer link Related questions What is the Product Rule for derivatives? How do you apply the product rule repeatedly to find the derivative of #f(x) = (x - 3)(2 - 3x)(5 - x)# ? How do you use the product rule to find the derivative of #y=x^2*sin(x)# ? How do you use the product rule to differentiate #y=cos(x)*sin(x)# ? How do you apply the product rule repeatedly to find the derivative of #f(x) = (x^4 +x)*e^x*tan(x)# ? How do you use the product rule to find the derivative of #y=(x^3+2x)*e^x# ? How do you use the product rule to find the derivative of #y=sqrt(x)*cos(x)# ? How do you use the product rule to find the derivative of #y=(1/x^2-3/x^4)*(x+5x^3)# ? How do you use the product rule to find the derivative of #y=sqrt(x)*e^x# ? How do you use the product rule to find the derivative of #y=x*ln(x)# ? See all questions in Product Rule Impact of this question 2070 views around the world You can reuse this answer Creative Commons License