Question

How do you find the derivitive of Inverse trig function `y=cot(1-2(x)^2)`?

Answer 1

`(4x)/(1+4x^4)`

Explanation:

Given function is y= `cot^-1 2x^2`

Cot y= `2x^2`. Now differentiate w.r.t x, to have `sec^2y dy/dx=4x`

`dy/dx= (4x)/(1+cot^2 y)= (4x)/(1+4x^4)`