How do you find the discriminant of the function f(x) = 2x^2-6x-3 and determine how many roots the function has?

1 Answer
Apr 4, 2018

Delta = 52
and this function has two real roots

Explanation:

Delta = B^2 -4AC

so we have

A=2,B=-6,C=-3

(-6)^2-4*2*(-2) = 36+16 = 52

Delta > 0 "

and that means we have 2 real roots to this function