How do you find the domain of #f(x)=Ln(3x+2)#?

1 Answer
Nov 18, 2016

Answer:

The argument of the #ln# function must be #>0#

Explanation:

#->3x+2>0# subtract #2#:
#->3x> -2# divide by #3#:
#->x> -2/3#
On the other side, there is no maximun for #x#, so:
#-2/3 < x < +oo# or #(-2/3,+oo)#

graph{ln(3x+2) [-5.37, 19.94, -6.49, 6.17]}