Question

How do you find the equation of a line tangent to the function `y=4x-x^2` at (2,4)?

Answer 1

`y=4`

Explanation:

`"the slope of the tangent is "dy/dx" at x =2"`

`dy/dx=4-2x`

`x=2tody/dx=4-4=0`

`"thus tangent is parallel to the x-axis"`

`"with equation "y=4`
graph{(y-4x+x^2)(y-0.001x-4)=0 [-10, 10, -5, 5]}