Question

How do you find the equation of the circle given center:(0,0) radius: 2 square root of 7?

Answer 1

The equation of a circle with center `(a, b)` and radius `r` is:

`(x-a)^2+(y-b)^2=r^2`

Explanation:

For this problem `a=0,b=0,r=2sqrt(7)`

Then the equation is:

`(x-0)^2+(y-0)^2=(2sqrt(7))^2`, that is:

`x^2+y^2=4*7`

So the equation is: `x^2+y^2=28`