# How do you find the equation of the circle given center (10, -7); and radius 8?

Aug 18, 2016

${x}^{2} + {y}^{2} - 20 x + 14 y - 85 = 0$.

#### Explanation:

The eqn. of a circle with centre $\left(h , k\right)$ and radius $r$ is given by,

(x-h)^2+(y-k)^2=r^2#.

In our case, the reqd. eqn. is ${\left(x - 10\right)}^{2} + {\left(y + 7\right)}^{2} = {8}^{2.}$, i.e.,

${x}^{2} + {y}^{2} - 20 x + 14 y - 85 = 0$.