How do you find the equation of the circle given center (-2,4) and radius 6? Precalculus Geometry of an Ellipse General Form of the Equation 1 Answer Mark D. May 25, 2018 #(x+2)^2+(y-4)^2=36# Explanation: #(x-a)^2+(y-b)^2=r^2# where (#a,b#) is the centre and #r# is the radius. #(x+2)^2+(y-4)^2=36# Answer link Related questions How can I tell whether an ellipse is a circle from its general equation? What conic section has the equation #x^2+y^2+12x+8y=48#? What comic does the equation #4x^2+4y^2=16# represent? How do I find the radius of a circle from its general equation? How can a general equation tell me whether a conic section is a circle or an ellipse? What conic section does the equation #x^2 + 4y^2 - 4x + 8y - 60 = 0 # represent? What conic section does the equation #−x+2y+x^2+xy+y^2=0# represent? What conic section does the equation #2x^2+4xy+6y^2+6x+2y=6# represent? What is the equation of a circle with a radius of 5? How do you find equation of ellipse with two vertices V1(7,12) and V2(7, -8), and passing... See all questions in General Form of the Equation Impact of this question 4816 views around the world You can reuse this answer Creative Commons License