How do you find the equation of the circle given Center: (3, -2); Radius: 3?

Mar 12, 2018

${\left(x - 3\right)}^{2} + {\left(y + 2\right)}^{2} = 9$

Explanation:

Standard equation of a circle ${\left(x - h\right)}^{2} + {\left(y - k\right)}^{2} = {r}^{2}$

$\left(h , k\right)$ being center of the circle

${\left(x - 3\right)}^{2} + {\left(y - \left(- 2\right)\right)}^{2} = {3}^{2}$

${\left(x - 3\right)}^{2} + {\left(y + 2\right)}^{2} = 9$