How do you find the equation of the circle given Center at the origin; r=squareroot 5?
1 Answer
Sep 1, 2016
Explanation:
The standard form of the equation of a circle is.
color(red)(|bar(ul(color(white)(a/a)color(black)((x-a)^2+(y-b)^2=r^2)color(white)(a/a)|)))
where (a ,b) are the coordinates of the centre and r, the radius.here the centre is at the origin, hence a = 0 , b = 0
andr=sqrt5 substitute into the standard equation.
(x-0)^2+(y-0)^2=(sqrt5)^2" simplifying to"
x^2+y^2=5" the equation of the circle" However, it is worth noting and remembering that when the circle is centred at the origin, the standard equation reduces to.
color(red)(|bar(ul(color(white)(a/a)color(black)(x^2+y^2=r^2)color(white)(a/a)|)))