# How do you find the equation of the line tangent to the graph of (2x^3 - 1) / (x²) at the point (1,1)?

Sep 16, 2015

$y = 4 x - 3$

#### Explanation:

$\left(2 {x}^{3} - 1\right)$/$\left({x}^{2}\right)$= $2 x - \frac{1}{x} ^ 2$
the derivative is slope of the tangent and is $2 + \frac{2}{x} ^ 3$
at x=1 the slope is 4
as point is (1,1) and slope is 4
general equation of a line is
$y = m x + c$
given m=4& (x,y)=(1,1)
substituting
$1 = 4 + c$
$c = - 3$
the equation of tangent is
$y = 4 x - 3$