How do you find the equation of the line tangent to the graph of tan x at the point where x=pi/4?
1 Answer
May 17, 2017
Explanation:
#"the gradient of the tangent " m=dy/dx" at " x=pi/4#
#rArrdy/dx=sec^2x#
#x=pi/4tody/dx=1/(cos^2(pi/4))=1/(1/2)=2#
#x=pi/4toy=tan(pi/4)=1#
#y-y_1=m(x-x_1)larr" point-slope form"#
#"here "m=2" and " (x_1,y_1)=(pi/4,1)#
#rArry-1=2(x-pi/4)" or "#
#y=2x-pi/2+1#
