How do you find the equation of the line tangent to #y=x^2# at (2,4)?
1 Answer
Sep 20, 2017
Explanation:
#•color(white)(x)m_(color(red)"tangent")=dy/dx" at x = a"#
#y=x^2rArrdy/dx=2x#
#x=2tody/dx=4#
#"using the point-slope form for equation of line"#
#y-4=4(x-2)#
#rArry=4x-4#