# How do you find the equation of the line that passes through the point (-2,5) and has slope m = -6/11?

##### 1 Answer
Mar 31, 2015

You may use the relationship:
$y - {y}_{0} = m \left(x - {x}_{0}\right)$
Where:
m is the slope and (${x}_{0} , {y}_{0}$) are the coordinates of your point.
So:
$y - 5 = - \frac{6}{11} \left(x - \left(- 2\right)\right)$
$y = - \frac{6}{11} x + \frac{43}{11}$

The relationship used for this problem derives directly from the definition of slope where you have:
$m = \frac{\Delta y}{\Delta x} = \frac{y - {y}_{0}}{x - {x}_{0}}$ with arbitrary ($x , y$).