How do you find the equation of the parabola vertex at the origin and the directrix at x=7?

1 Answer
Jan 10, 2016

With a vertex =(0,0)=(0,0) and directrix x=7x=7, this parabola opens to the left and will be of the form x=(1/(4c))(y-k)^2+hx=(14c)(yk)2+h

Explanation:

The absolute distance between the directrix and vertex c=7-0=7c=70=7

So, the coefficient 1/(4c)=1/(4xx7)=1/2814c=14×7=128

The sign of the coefficient must be NEGATIVE because the parabola opens to the left.

vertex =(0,0)=(h,k)=(0,0)=(h,k)

Finally, substitute the values into the equation ...

Equation : x=(-1/(28))(y-0)^2+0=-(y^2)/28x=(128)(y0)2+0=y228

hope that helped

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