How do you find the equation of the tangent and normal line to the curve #y=(2x+3)/(3x-2)# at #(1,5)#?
the general point
Also, the tgt. passes through
Therefore, by the Slope-Pt. Form , the eqn. of tgt. is,
As regards the eqn. of the Normal, it is
So, the eqn. of normal is