# How do you find the equation of the tangent and normal line to the curve #y=x+cosx# at #x=1#?

##### 1 Answer

Dec 26, 2016

#### Explanation:

The point of contact is (1, 1.5403)

y' ar x = 1 is

So, the equation of the tangent is

The tangent crosses the curve, elsewhere.

The normal to the curve is given by

graph{(y-0.16x-1.38)(y-x-cos x)(y+6.31x-7.84)=0 [-20, 20, -10, 10]}