Question

How do you find the equation of the tangent line of `y= x^7- 6x^5-3` at x=1?

Answer 1

`y=-23(x-1)-8`

Explanation:

`y=x^7-6x^5-3`

`y(1) = (1)-6(1)-3=-8`

`dy/dx = 7x^6-30x^4`

`dy/dx|_(x=1) = 7(1)-30(1)`

`=-23`

Equation of tangent line:
`y=-23(x-1)-8`