Question

How do you find the equation of the tangent line to curve `y=x^3 - 2x` at the point (2,4)?

Answer 1

If `y=x^3-2x`
then
`y' = 3x^2-2`
and the slope of the tangent at `(2,4)`
is `3(2)^2-2 = 10`

In point-slope form the equation of the tangent through `(2,4)`
is
`(y-4) = 10(x-2)`