How do you find the equation of the tangent line to the graph of #f(x)=x^2+1# at point (2,5)?
1 Answer
Jan 16, 2018
Explanation:
#m_(color(red)"tangent")=f'(x)" at x = 2"#
#rArrf'(x)=2xrArrf'(2)=4#
#y-5=4(x-2)#
#rArry=4x-3larrcolor(blue)"is equation of tangent"#
