Question

How do you find the equation of the tangent line to the graph of `y = ln x^2` at the point (2, ln 4)?

Answer 1

`y-ln4=1(x-2)`

Explanation:

`y=2lnx`->use property `log_bx^n = nlog_bx`
`y'=2*1/x = 2/x=2/2 = 1`
`y-ln4=1(x-2)`