# How do you find the exact value of log_2 sqrt2?

$\frac{1}{2}$
${\log}_{2} \sqrt{2} = {\log}_{2} {2}^{\frac{1}{2}}$
=$\frac{1}{2} {\log}_{2} 2$ (${\log}_{2} 2$ equals 1)
=$\frac{1}{2}$