# How do you find the exact value of log_3 81^-0.2?

Dec 29, 2016

$- 0.8$

#### Explanation:

Since $\log {a}^{b} = b \log a$,

the given expression becomes:

$- 0.2 {\log}_{3} 81$

$- 0.2 {\log}_{3} {3}^{4}$

$- 0.2 \cdot 4$

$- 0.8$