How do you find the exact value of #log_4 2+log_4 32#?

Question

13512 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-01-12T19:23:27

Use the property: #log_4(2) + log_4(32) = log_4(2xx32) = log_4(64)#
#log_4(64) = log_4(4^3) = 3#
#log_4(2) + log_4(32) = 3#