# How do you find the exact value of log_4 2+log_4 32?

Use the property: ${\log}_{4} \left(2\right) + {\log}_{4} \left(32\right) = {\log}_{4} \left(2 \times 32\right) = {\log}_{4} \left(64\right)$
${\log}_{4} \left(64\right) = {\log}_{4} \left({4}^{3}\right) = 3$
${\log}_{4} \left(2\right) + {\log}_{4} \left(32\right) = 3$