# How do you find the first and second derivative of (ln(x))^2?

$d \frac{{\left(\ln x\right)}^{2}}{\mathrm{dx}} = 2 \cdot \ln x \cdot d \frac{\ln x}{\mathrm{dx}} = 2 \cdot \ln x \cdot \frac{1}{x}$
$d \frac{2 \cdot \ln \frac{x}{x}}{\mathrm{dx}} = 2 \cdot \frac{\ln x ' \cdot x - \ln x \cdot x '}{{x}^{2}} = 2 \cdot \frac{1 - \ln x}{{x}^{2}}$