Question

How do you find the first and second derivative of `(ln(x))^2`?

Answer 1

The first derivative is

`d((lnx)^2)/dx=2*lnx*d(lnx)/dx=2*lnx*1/x`

The second derivative is

`d(2*lnx/x)/dx=2*[lnx'*x-lnx*x']/[x^2]=2*(1-lnx)/(x^2)`