Question

How do you find the first and second derivative of `y=2^-x`?

Answer 1

`f'(x)=-2^(-x)ln2`

Explanation:

The derivative of any function such as `b^x` is `b^xlnb`. Knowing that, we can clearly see b is 2. But since it's a negative x, we must use chain rule and multiply by `-1`

`f(x)=2^(-x)` will become `f'(x)=-2^(-x)ln2`