# How do you find the first five terms given a_1=4 and a_(n+1)=3a_n-6?

Sep 16, 2017

$\left\{4 , 6 , 12 , 30 , 84\right\}$

#### Explanation:

${a}_{n + 1} = 3 {a}_{n} - 6$

${a}_{1} = 4$

${a}_{2} = 3 {a}_{1} - 6 = 3 \times 4 - 6 = 12 - 6 = 6$

${a}_{3} = 3 {a}_{2} - 6 = 3 \times 6 - 6 = 18 - 6 = 12$

${a}_{4} = 3 {a}_{3} - 6 = 3 \times 12 - 6 = 36 - 6 = 30$

${a}_{5} = 3 \times {a}_{4} - 6 = 3 \times 30 - 6 = 90 - 6 = 84$