How do you find the first five terms of each sequence a_1=0a1=0, a_(n+1)=-2a_n-4an+1=−2an−4?
1 Answer
Jul 2, 2017
{0,4,-12,20,-44} {0,4,−12,20,−44}
Explanation:
We have a sequence:
{a_n} = {a_1, a_2, a_3, ... }
Where:
\ \ \ \ a_1 =0
a_(n+1) = -2a_n-4
Put
Put
Put
Put
Thus the first five terms
{0,4,-12,20,-44}