How do you find the first five terms of the sequence #a_1=3#, #a_(n+1)=2a_n-1#?

1 Answer
Nov 6, 2016

Answer:

3,5, 9,17,33

Explanation:

#a_(n+1)=2a_n-1#
So if #a_n=3# then #a_(n+1)#=. 2 x 3 - 1. = 5

#a_(n+1)# is the next term in the sequence after #a_n#
And #a_n=5# then #a_(n+1)#=. 2 x 5 - 1 = 9
#a_n=9# then #a_(n+1)# =2 x 9 - 1 = 17
And the next term 2 x 17 - 1 = 33

The sequence increases by powers of 2!