How do you find the first three iterate of the function f(x)=9x-2 for the given initial value x_0=2?

Dec 20, 2017

$16 , 142 , 1276$

Explanation:

$\text{by substituting "f(x)" into the previous one}$

${x}_{1} = f \left({x}_{0}\right) = f \left(2\right) = 9 \left(2\right) - 2 = 16$

${x}_{2} = f \left({x}_{1}\right) = 9 \left(16\right) - 2 = 142$

${x}_{3} = f \left({x}_{2}\right) = f \left(142\right) = 9 \left(142\right) - 2 = 1276$