How do you find the fourth partial sum of #Sigma 5(1/2)^i# from i=1 to #oo#?
A series is an infinite sum, i.e. a sum with infinite terms.
Partial sums are approximations of the series, where you reduce it to a finite number of terms. In fact, the
So, the fourth partial sum is the sum of the first
First of all, let's factor the
Now we can simply translate the notations, plugging