How do you find the GCF of #14n, 42n^3#?

1 Answer
Mar 7, 2018

Answer:

See a solution process below:

Explanation:

Find the prime factors for each term as:

#14n = 2 xx 7 xx n#

#42n^3 = 2 xx 3 xx 7 xx n xx n xx n#

Now identify the common factors and determine the GCF:

#14n = color(red)(2) xx color(red)(7) xx color(red)(n)#

#36 = color(red)(2) xx 3 xx color(red)(7) xx color(red)(n) xx n xx n#

Therefore:

#"GCF" = color(red)(2) xx color(red)(7) xx color(red)(n) = 14n#