How do you find the geometric mean between 81 and 4?

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Answer 1 · 2018-06-01T16:11:31

$18$

the geometric mean of two numbers $" "a,b$

$G_m=sqrt(ab)$

we have

$G_m=sqrt(4xx81)$

$=9xx2=18$

Answer 2 · 2018-06-01T16:14:19

$G=sqrt(81xx4)=sqrt(9^2xx2^2)=9xx2=18$

We know that,

Geometric Mean $G$ of two numbers $a and b$ is :

$G=sqrt(ab)$

Let, $a=81 and b=4$

So,

$G=sqrt(81xx4)=sqrt(9^2xx2^2)=9xx2=18$