Question

How do you find the indefinite integral of `int ((6e^(1/x))/x^2)`?

Answer 1

`int(6e^(1/x))/x^2dx=-6e^(1/x)+C`

Explanation:

You can calculate this integral by substitution `t=1/x`

`int(6e^(1/x))/x^2dx=|(t=1/x),(dt=-1/x^2dx),(-dt=dx/x^2)|=`

`=int6e^t*(-dt)=-6inte^tdt=-6e^t+C=-6e^(1/x)+C`