Question

How do you find the indefinite integral of `int (cot(x))^(1/26) csc(x)^2 dx`?

Answer 1

`I=-26/27cotxroot(26)(cotx) +C`

Explanation:

I presume that you mean `(cscx)^2`

`cotx=t => -csc^2xdx=dt`

`I=int (cotx)^(1/26)(cscx)^2dx=-int t^(1/26)dt=-t^(27/26)/(27/26)+C`

`I=-26/27cotxroot(26)(cotx) +C`