Question

How do you find the indefinite integral of `int sin^3xcosxdxdx`?

Answer 1

`int sin^3xcosxdx = 1/4sin^4x +C`

Explanation:

Let `u=sinx`
Then, `(du)/dx = cosx => int ...du = int ...cosxdx`

Substituting into the integral gives:

`int sin^3xcosxdx = int u^3du`
`:. int sin^3xcosxdx = 1/4u^4 +C`
`:. int sin^3xcosxdx = 1/4sin^4x +C`