How do you find the indefinite integral of $int ( (sin(x))^2 - (cos(x))^2 ) / (sin(x))$ ?

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Answer 1 · 2015-09-21T02:38:54

$-cosx+cotx+c$

$int (sin^2x-cos^2x)/sinxdx=int(sinx-cosx/(sinx*sinx))dx$
$intsinxdx-intcotxcosecxdx=-cosx+cotx+c$

How do you find the indefinite integral of int ( (sin(x))^2 - (cos(x))^2 ) / (sin(x))int ( (sin(x))^2 - (cos(x))^2 ) / (sin(x))?