Question

How do you find the inflection points for the function `f(x)=8x+3-2 sin(x)`?

Answer 1

Solve the equation `sin(x)=0` and it must be `cos(x)ne 0`

Explanation:

`f(x)=8x+3-2sin(x)`
`f'(x)=8-2cos(x)`
`f''(x)=2sin(x)`
`f'''(x)=2cos(x)`