Question

How do you find the integral of `x^2 e^(-x) dx`?

Answer 1

`-x^2 e^-x -2xe^-x -2e^-x` +C

Explanation:

This can be solved, intergrating it by parts,

I= `-x^2 e^-x - int 2x (-e^-x) dx`

= `-x^2 e^-x +2 int xe^-x dx`

=`-x^2 e^-x +2( -xe^-x - int -e^-xdx )`

=`-x^2 e^-x -2xe^-x -2e^-x` +C