How do you find the integral of #x^2(sec(x^3))^2#?
1 Answer
Jun 11, 2016
Explanation:
We want to integrate:
#intx^2(sec(x^3))^2dx#
Let
#1/3int3x^2(sec(x^3))^2dx#
Substitute in
#=1/3int(sec(u))^2du#
Note that the derivative of
#=1/3tan(u)+C#
Since
#=1/3tan(x^3)+C#