How do you find the integral #(x^4)(lnx)#?

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Answer 1 · 2018-04-06T07:32:27

#x^3-4/3(x^3) + c#

Integration by parts is
#int utimes (dv) = uv- intv du#

Apply it to this integral:

#int(x^4)(In x) dx#

#u=x^4#
#dv=In x#
SO #v=1/x#

= #x^4times1/x- int1/xtimes4x^3 dx#

= #x^3-4intx^2 dx#

= #x^3-4/3(x^3) + c#