How do you find the intercepts of $x^2y-x^2+4y=0$ ?

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Answer 1 · 2015-03-24T02:22:19

For the intercepts you set alternately $x=0$ and $y=0$ in your function:
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and graphically:

Answer 2 · 2015-03-24T02:22:53

On the X-axis $y=0$
So
$x^2y -x^2 + 4y = 0$
becomes
$x^2(0) - x^2 + 4(0) = 0$
$rarr -x^2 = 0$
$rarr x = 0$

On the Y-axis $x=0$
and the original equation
$x^2y -x^2 + 4y = 0$
becomes
$(0)^2y -(0)^2 +4y = 0$
$rarr y=0$

The only intercept for the given equation occurs at $(0,0)$

How do you find the intercepts of x^2y-x^2+4y=0x^2y-x^2+4y=0?