# How do you find the intervals on which the graph of #f(x)=5sqrtx-1# is concave up or is concave down, and find the x - coordinates o the points of inflection?

##### 1 Answer

May 26, 2015

Unless required, I would not use calculus for this.

The graph of the square root function is:

graph{y=sqrtx [-1.34, 11.146, -1.744, 4.5]}

In

It is clear that the graph is concave down on

Since the concavity does not change, there are no inflection points.

If I am required to use calculus:

Note that the domain of

Therefore, the graph of