How do you find the inverse of #A=##((6, -2), (9, -3))#?
A has no inverse.
To find the inverse of a 2 X 2 matrix , consider the following.
If A =
#((a,b),(c,d)) " then " A^-1 = 1/(ad - bc)((d,-b),(-c,a))#
ad - bc , is the determinant of the matrix , and if equal to zero , then no inverse exists and the matrix is singular.
for matrix here: a = 6 , b=-2 , c = 9 and d = -3
# ad - bc = (6xx-3) -(-2xx9) = -18 + 18 = 0#
result is that matrix A has no inverse.