# How do you find the inverse of f(x)=32x^5?

Oct 5, 2015

${f}^{-} 1 \left(x\right) = \sqrt[5]{\frac{x}{32}}$

#### Explanation:

Let $f \left(x\right)$ be $y$.

$y = 32 {x}^{5}$

Make $x$ the subject.

${x}^{5} = \frac{y}{32}$

$x = \sqrt[5]{\frac{y}{32}}$

Then switch the $y$ into $x$ to get the final answer.

${f}^{-} 1 \left(x\right) = \sqrt[5]{\frac{x}{32}}$