Question

How do you find the inverse of `f(x)=x^3-1`?

Answer 1

`f^-1(x)=(x+1)^(1/3)`

Explanation:

`y=x^3-1`

`y+1=x^3`

`x=(y+1)^(1/3)`

Thus `f^-1(x)=(x+1)^(1/3)`