How do you find the inverse of #f(x) =x^3-2#?

1 Answer
Oct 14, 2015

#root(3)( x+2)#

Explanation:

Equate f(x) to some variable, say y. f(x)=y.

So,
#x^3-2=y#
#x^3=y+2#
x=#root(3)(y+2)#

Now swap in #x# for #y#. And f(x) inverse is= #root(3)(x+2)#

(Sorry if the formatting is wrong, I'm pretty new here but as the answer reads, f inverse of x is equal to cube root of x plus 2)