Question

How do you find the inverse of `g(x) = 2(7)^x`?

Answer 1

`g^(-1)(x)=ln(x/2)/ln(7)`

Explanation:

Let
`y=2*7^x`
then we get
`y/2=7^x`
Taking the logarithm on both sides
`ln(y/2)=xln(7)`
so
`x=ln(y/2)/ln(7)`
changing the variables
`g^(-1)(x)=ln(x/2)/ln(7)`